0=-16x^2+199x+90

Solution for 0=-16x^2+199x+90 equation:

0=-16x^2+199x+90

We move all terms to the left:

0-(-16x^2+199x+90)=0

We add all the numbers together, and all the variables

-(-16x^2+199x+90)=0

We get rid of parentheses

16x^2-199x-90=0

a = 16; b = -199; c = -90;
Δ = b2-4ac
Δ = -1992-4·16·(-90)
Δ = 45361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-199)-\sqrt{45361}}{2*16}=\frac{199-\sqrt{45361}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-199)+\sqrt{45361}}{2*16}=\frac{199+\sqrt{45361}}{32}
$